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A battery with E = 12.0 V and internal resistance r=1.2Ω is connected to two 8.5-kΩ...

A battery with E = 12.0 V and internal resistance r=1.2Ω is connected to two 8.5-kΩ resistors in series. An ammeter of internal resistance 0.30 Ωmeasures the current, and at the same time a voltmeter with internal resistance 17 kΩ measures the voltage across one of the 8.5-kΩ resistors in the circuit.

What does the ammeter read?

What does the voltmeter read?

What is the % "error" from the current without meters?

What is the % "error" from the voltage without meters?

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