Question

(a) What is the equivalent resistance of five resistors connected in series with a 12.0-V battery if each resistor has a value of 19.0 ? (b) Determine the current flowing through each of the five resistors. A (©) If the five resistors were instead connected in parallel across the battery, what would be the equivalent resistance? (d) Determine the current through each resistor for this parallel connection. А Submit Assignment Save Assignment Progress

Answer 1

Given: V = 12.0V & R = R₂ = Rp = Rg= Rq = Q = 19.22 a) When resistances are in series then equivalent resistance is, R = R + R2 + Rg tRq tRp = RTR+R+RER=ER Rs: 5x19 Rs = 952 b) Since, all resistors are connected in series, current foloing through each resistor is same. ... From Ohms law, 12 V=IRS = I= Rs 95 1: I = 0.1263 A c) kchen resistors are connected in parallel then equivalent resistance is, tett +++++ tattdelet Rp - RR RR Rq Rs R RR RR 5 R Rp = 19 5 5 - Rp= 3.802 d) since, all resistors are connected in parallel, therefore potential difference across all the resistor is same. . From Ohms law, V= I Rp = I= V Rp 12 3.8 . I= 3.1579 A Here, all the resistors posses same value therefore current flowing through each resistance is also same. (i.e, I = 3.1579A