Question

1 of 4 ChE 2410 - Introduction to Chemical Process - Discussion 3 Due: Before 11:59 pm on Friday 09/20/19. Submissions must be submitted to backboard in the form of a single pdf file. Late submissions will receive zero points. Name: 1) An open-end mercury manometer is to be used to measure the pressure in an apparatus containing a vapor that reacts with mercury. A 10-cm layer of silicon oil (SG = 0.9) is placed on top of the mercury in the manometer arm attached to the apparatus. Atmospheric pressure is 1 atm. If the level of mercury in the open end of the manometer is 500 mm below the mercury level in the other arm, what is the pressure (kPa) in the apparatus?

Answer 1

Apparatus oil Atmospher's Pressure неше * AB BC = 10 on - Soo mm = 0.1m = o. sm 0.9 13.6 S.G. of silicon ou = S.G. of mercury = Dersity = S.G. x 1000 ugim? [1000 is dersity of water] ² Dersity Density of of silicon oil = Mercury Mercury : = 0.9 x 1000 13.6 x 1000 = 900 regim3 = 13600 Kolme → Pressure at P (Po) : = 1 atm 101325 Pa (open to (I atm atmosphere) = 101325 Pa) material at same ever By Pascals law connected funds of same exert equal pressure. & Pressure at c = Pressure at D 101325 Pa

variation of pressure with height Ch is given as: ДР 7 8 }шid 7 ях, 1.4. Pressure at lower point - Pressure at Higher Pant = Shuid gth - Pe - PB = 5 mercury & g * BC : (01325 13600 x 9.81 * 0.5 101325 .- 66708 = 34617 Pa 12 Pa Similarly Po-PA = Iwate & g x AB +0.1 & 1 34617 - PA = 1000 x 9.81 PA = 34617 - 981 33636 Pa 33. 636 Kpq » 1 Thus, Pressure in apparatus - PA = 33.636 lpa