Ans 8) population of snail in April = 38 = initial population = N0
Population of snail after 4 months = 214 = final population = Nt
Time = t = 4 months = 4/12 years = 1/3 year
Ans a) growth rate of snail population.
R = ∆N / t
R = growth rate
∆N = Nt - N0
t = time
Putting all values in formula. We get,
R = 214 - 38 / 1/3.
= 176 * 3/1
= 528 snails/year
Ans b) per capita growth rate of population is
r = (∆N/N0 * 100)/t
r = (176/38 * 100) / 1/3
= (17600/38) / 1/3
= 463.16 / 1/3
= 463.16 * 3
= 1389.48% per year
Ans 9) 2 factors that determine where population is distributed are :
1) physical factors ---:> include the physical conditions of a place like the climatic conditions, soil type, landform, water bodies,etc. These are the basic requirements of population to live in.
2) human factors -----> include the human nature or behaviour like the culture and tradition, the economic conditions, politics, history.
Ans 10) the population distribution pattern in Canada is not uniform. Most people live in southern part than in Northern part.
can someone help me with this whole page questions. i dont know how to do it....
i dont know how to do this question can someone help me Highlight Rotate M OH (8 pts Total) Answer the following questions about p-methoxybenzoic acid. a. On the structure to the right, use letters to label and indicate chemically equivalent and distinct hydrogens. Be sure to label each hydrogen. (3 pts) O-CH3 b. Calculate the estimated chemical shift of the hydrogen at the position indicated by the arrow using the table at the beginning of this exam. Show and...