Question

Question Systems: Consider the following system for the questions below (indicate relevant transition points and peak values when drawing frequency domain representations). Note that X (jw) is the frequency domain representation of the input and both filters use a scaled version of the filter, H(jw). y(t) x(t)- H(w) H(jw) cos(2w.t) H(w) W(0) -Wo Wo X(jw) -2wo-WOW O 2w, a) Draw the frequency response of the output of the first signal path, Y. (jw) b) Draw the frequency response of the input to the second filter, W (jw)

Answer 1

x(+) H(jw)} $(4) wit) H() col zwit x(im) w, 2w, 3ub -3w - 2W, -W. -W. Y,lH= n(t) * hit) Yiliw) = x (w) H(j) { io? ; -w, cWsW. x (jw) Y, lju) = othenwire Wo ntt) col (2w,t) WHI= (x (aw) * I{S(w-2w,) + 5(w+ 24)}] wfw) = {(x (w-2ws) + x (w+2w)] wiwl = E (Ja) 으 1(w) -Wo 2w, 3w. Sjw, Swo Wo Su, tw, -3w, -2w, -W,

m. swo 2W. 3W. - Swo -4W, -3wo -2Wo -Wo wIt) * ht) Y2 (ju) = w(jw) H(j) J W(Ju) ; -wo cW< Wo Y2(jW)- ; other wire. - W.