Question

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3. The truss has a pinned support at A and a roller support at C. i. If P = 0 kN and P2 = 5 kN, list all of the zero-force members in the truss (10 points) ii. If P1 = 30 kN and P2 = 16 kN, the support reaction at C is Roy = 28 kN (pointing up) Determine the forces in all members of the truss. Clearly indicate if each member is in tension or compression (20 points). Fill out the table and show all your work. Use this table for Partii ONLY Member Force (kN) Tension/Compression AB BC FA AE

Answer 1

Pi=0 Reactions Reactions Ax=0 Ay+Cy=5 Ay Monstanta & Scy MA = (-5x3) + Cyx6=0 P2=5kN Cyx6 = 5x3 Cy= 2.6 KN at Joint o Ay = 2.4KN FDE For=0) at Jomt Pao *FEF FAFFO] AFO & FAF
is
Pi-BORN [Ax=-30KN 4M Ay+cy = 16 KN MA= (-16x3) - (30х4) tryXG=0 y = a8kW 13 km 0 P2 = 16 KN ar Ay=16-28 (Ay = -12 KN at Jomt F P = 30 KN FAF = 0 EF FEF = -30KN & FAF

at Joint B 4 Гвс IFBE = IG KN FAB FBC FAB = FBC * P2 = 16 kN at Joint D FDE [For=0] Fro=o & Foo at Joint a 4 Fon Eco Tomo = 4/3 & Fresing 0 = 53.13 Frecoso FBC Toy FBC

Cy+ Foot FCE Sing=0 38 + 0 + FCE Sim 53.13=0 FCE =-20 Sin 53.13 FCE =-25 KN FBC = - FCE COS 53:13 = 8500553.13 FFBC = 15 kn at Joint A 4 FAF & FAE Gese sino 4 FAF FAE - FAECOSP. AX=-30W FAB K0=5313 FAB 4 Ay = -12 KN FAFT FAE Sím 53-131-12 = 0 0+ FAE Sim 53-13 =12 FAE = 15 kn

Member Forle (KN) Naturare AB tunsion tension DE EF Compressive FA AE tension BE tension CE Compressive