Question

The mole fraction of nickel(II) acetate, Ni(CH3COO)2, in an aqueous solution is 3.76x102 The percent by mass of nickel(II) acetate in the solution is 0 Submit Answer

Answer 1

1)

Let the total mol in solution be 1 mol

Then mol of Ni(CH3COO)2 is 3.76*10^-2 mol

mol of H2O = 1 - 3.76*10^-2 mol

= 0.9624 mol

Molar mass of Ni(CH3COO)2,

MM = 1*MM(Ni) + 4*MM(C) + 6*MM(H) + 4*MM(O)

= 1*58.69 + 4*12.01 + 6*1.008 + 4*16.0

= 176.778 g/mol

use:

mass of Ni(CH3COO)2,

m = number of mol * molar mass

= 3.76*10^-2 mol * 1.768*10^2 g/mol

= 6.647 g

Molar mass of H2O,

MM = 2*MM(H) + 1*MM(O)

= 2*1.008 + 1*16.0

= 18.016 g/mol

use:

mass of H2O,

m = number of mol * molar mass

= 0.9624 mol * 18.02 g/mol

= 17.34 g

mass % = mass of Ni(CH3COO)2 * 100 / total mass

= 6.647 * 100 / (6.647 + 17.34)

= 27.7 %

Answer: 27.7 %

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