Answer
concentration of Ammonium Sulphate in the solution is 20.31%w/v
Question 2 0/1 pts A solution was prepared by dissolving 8.03 g of (NH4)2SO4 (MW =...
A solution is prepared by weighing 7.345g of (NH4)2Ce(NO3)6 (548.2 g/mol) and then dissolving it in water to a final volume of 900.0 ml. a) the concentration of the cerium solution is ________ b) the correction for the indicator is a) subtract 0.05 ml b) add 0.05 ml c) none c) 12.00 ml of iron (ii) solution is titrated with this cerium solution, and it requires 19.55 ml. the concentration of the Fe(ii) is __________M.
A solution is prepared by dissolving 78 0 g of glucose (C6H1206 ) in 150 g of water. The final volume is 228 ml Calculate the Molarity (MM of glucose is 180 18 g/mol and MM of water is 18.02 g/mol) For units do not use fractional units like g/mol or g/mL QUESTION 23 A solution is prepared by dissolving 78.0 g of glucose (C6H1208) in 150 g of water. The final volume is 228 ml Calculate the Molality (MM...
1 UUTIUSIS 2. What is the concentration of a solution prepared by dissolving 30 grams of Sodium Chloride in 45 ml of water? Express the concentration in % (m/v) 3. What is the concentration of a solution prepared by dissolving 23 ml of HCl to a final volume of 400ml? Express the concentration in % (v/v).
A solution is prepared by dissolving 0.300 g Fe(NH4)2(SO4)2*6H2O in sufficient water to produce 250.0 mL of solution. a. What is the molar concentration of Fe2+? b. What is the molar concentration of NH4+? c. What is the concentration of sulfur in mg/L?
2. (10 points) A solution at T - 25 °C is formed by dissolving 4.38 g of glucose (CHO, MW - 180.2 g/mol), a nonvolatile and nonionizing solute, in water (H-0, MW - 18.02 g/mol). The final volume of the solution is V - 250.0 mL. Based on this information, find the osmotic pressure of the solution. Give your final answer in units of ton
a solution was prepared by dissolving 27.0 g KOH in 100 g water. A) what is mole fraction of KOH in solution? B) what is mass percent?C) what is the molality? 2. A solution was prepared by dissolving 27.0 g KOH(s)in 100.0 g water. You may use the chart below if you find usefiul to answer questions a) -e) MW (g/mol Mass ()moles 56.1 H20 18.0 Solution (a) What is the mole fraction of KOH in the solution? (5 pts...
(10 pts) A solution is prepared by dissolving 1.239 grams of hydrochloric acid, HCI, in enough water to make 250.0 mL of solution. A 25.00 mL sample of this solution is diluted with water to a final volume of 100.0 mL. Now, you take 10.00 mL of that solution and dilute it to 100.00 mL What is the molarity of the final solution? (HCI 36.45 g/mol)
2. A student prepared a stock solution by dissolving 15.0 g of NaOH in enough water to make 150 mL of a stock solution. She then took 22.5 mL of the stock solution and diluted it with enough water to make 250. mL of a working solution. (5 pts. each) A. What is the molar concentration of NaOH in the stock solution? # of moles x 1000 Naot mass= 15,09 g molanty volume of source (m) Mol 40 g/mol voline...
Calculate the molality of a dextrose (mw = 180.16 g/mole) solution prepared by dissolving 52.8 g dextrose in 500 mL of water (density of the solution is 1.06).
8.- An aqueous solution is prepared dissolving 10.000 g of compound Z (MW-200.0) in 200.0 mL of solution. If 16.0 mL of that solution are added to 84.0 mL of water, the final molarity is a) 0.0800 M b) 0.0200 M c) 0.0100 M d) 0.0400 M