Question

1. The moon's orbital speed around Earth is 3.680 x 109 km/h. Suppose the moon suffers a perfectly elastic collision with a comet whose mass is 50.0 percent that of the moon. (A partially inelastic collision would be a much Problem G DATE CLASS more realistic event.) After the collision, the moon moves with a speed of -4.40 x 102 km/h, while the comet moves away from the moon at 5.740 x 109 km/h. What is the comet's speed before the collision?

Answer 1

5.74 x 0 - 8 8 x 102 vel = 2.5x 103 kathr. speed of Comet before Collision Vc = -2500 KM/hr Assume linear motion of mach a comet for a moment When Collision occurs. 2m m. Q 3.68x10 2 2M 4. uxlo A Ve m 10 a 5.740x 10 kenahr. A Just before. Collision occurs Jast After collision occurs ib, mass of Comet 8 m - 2m mass of moon Apply momentum conservation = m Vc + 2m (3.68 x 103) Vct 7.36610 m (5.74x103) – 2m (4.4x18) Vc = - 2.500 x 103 kml hr. or-2.5X103 kmlhr