Question

1) a) Find the current, I, in the circuit. (15 points) b) Find the power delivered to all elements and show that power is conserved (5 points) 50 V 10 12 I + 10 V +1 M M. 422 522

Answer 1

R-1002 50V 10 1' = 10-416.005) lov I' 142 5.52 se, I 1' = 1oo14 A Torrent will just be in reverse direction of what AD assumed - 1) Applying KVL to , we get, 10 - 4(1+1') - 101' = 0 -0 Applying KVL to ③ we get, 50 - 51 - 4 (1+1') = 0. - (2) 7 - 41 - 141' = -10. → U1 + 141 -10 . (3) x-91-uI' = -50 91 +UI' = 50 (u) Power delivered to: R, 7P: 1'²R, : 11.0014) ² 10w. = 10.02w RP₂ = 1² R₂ + 1 1 ² R2 (6.005)² 4 we = 148.24 W R, ЭР, 1² R₂ = (6.005)²5 W = 180.3W froon ea(3) I-10-UI 14 putting in ego (u), we get, 91 + y (10-01) - 50 14 91 +40 16 I = 50 14 14 22/9-16) SO - 20 7 2 1 = 47.14 A -16.005A 7.85