Question

2.1 problem v(t) (v) 2Vm t (s) -2V - Refer to Homework 1.1. Compute an approximation of Vrms using harmonic terms up to and including n = 11, that is, compute Show that the relative error between this approximation and the exact rms value Vrms = V.V2 is approximately 1.3%. Answer: 1.396V... 1.3% Pueblom 2.2

Answer 1

#fucblem 21 Given wavefcom is a six pulse wavef091m. na feuniey Series Expression of six-pulse f(m) = 6X Sinanwt10) whene x = amplitude of ungle pule here X= VM FG) - CV Sin/nwt+0) buy 63 bis 677--. can be obtain by putting the value of n as 43,5,7,9,11 b1 = tym :; b3 = Sum bs= 67 = Elm bq = 6lm bir = 6 m Equivalent RMS voltage Gum)? JIMIN 36 m² 360m² 368m2 36 Vro² 36ima 2K²2x9x22x2572 2x4972+ 2x2 172 4 36Vm 2x12173

Vorms a VM 2 tang tatt ta + 8 + 121 25 Veams 1.396 Vm Vaims & 1-396 vm] Vm= maximum Voltage of single pulse... Relative E92104? Erion = Toute valitto measured values 100 Poruc vattee Torus value = Vmi - dum - saxim Touw value = 1.414 Vm. Error = 7:474-7:396 x100 = 1.28% 1.396 | Ex100= 1:36% Meas. pepper