Solution A was prepared from 0.2703g of ferrous ammonium sulfate [Fe(SO4)2(NH4)2• 6H20; Molar mass = 392.2g/mole]...
Solution A was prepared from 0.2703g of ferrous ammonium sulfate [Fe(SO4)2(NH4)2• 6H20; Molar mass = 392.2g/mole] dissolved in 100.0 mL of distilled water. Show all work for full credit.
(a) Calculate the molarity of solution A. (Remember molarity = moles/Liter)
Solution B was prepared by pipeting 25.00 mL of solution A into a 250.0 mL volumetric flask, and then the flask was diluted to the mark (exactly 250.0 mL, Vb) with distilled water.
(b) Calculate the molarity of solution B. (Hint: MAVA = MBVB)
(c) How many millimoles of Fe2+ are present in a 10.00 mL sample of solution B ? (Hint: millimoles in solution B = mL x molarity of solution B)
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Solution A was prepared from 0.2703g of ferrous ammonium sulfate
[Fe(SO4)2(NH4)2•
6H20; Molar mass = 392.2g/mole]...
A solution is prepared by dissolving 0.300 g Fe(NH4)2(SO4)2*6H2O in sufficient water to produce 250.0 mL...
A solution is prepared by dissolving 0.300 g Fe(NH4)2(SO4)2*6H2O in sufficient water to produce 250.0 mL of solution. a. What is the molar concentration of Fe2+? b. What is the molar concentration of NH4+? c. What is the concentration of sulfur in mg/L?
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1.1 Accurately (using an analytical balance ONLY) weigh 1.4 g of Fe(NH4)2(SO4) 2-6H20 1.2 Dissolve in 50 mL of 4% sylturisacid in a beaker. 1.3 Transfer into a 1 L volumetric flask; adjust the volume and mix well. Note the purity of the Fe(NH4)2(SO4)2.6H20 given on the label of the container. 1.4 Transfer this solution into a 1 L glass bottle. Preparation of working iron standard solution: 1.5 Pipet 10.00 mL of the iron standard stock solution into a 500.0...
(10 pts) A solution is prepared by dissolving 1.239 grams of hydrochloric acid, HCI, in enough water to make 250.0 mL of solution. A 25.00 mL sample of this solution is diluted with water to a final volume of 100.0 mL. Now, you take 10.00 mL of that solution and dilute it to 100.00 mL What is the molarity of the final solution? (HCI 36.45 g/mol)
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