Question

A battery is constructed at 25ºC using the voltaic cell with initial concentrations Zn│Zn2+ (0.100 M)...

A battery is constructed at 25ºC using the voltaic cell with initial concentrations

Zn│Zn2+ (0.100 M) ││Ag+ (1.500 M) │Ag

How much does the cell voltage drop when 95% of the capacity (i.e., the concentration of Ag+ drops to 5% of its starting value) is consumed?

The standard reduction potentials for the two half-cells are

Zn2+ + 2e- → Zn Eº = − 0.76 V Ag+ + e- → Ag Eº = 0.80 V

0 0
Add a comment Improve this question Transcribed image text
Answer #1

ba/ an reacsion ig nal comc 007Sm is consumed nl1 be Formed 吃.rm: [0-1 + ⅓[1.s-o.o3r) cone, : 0-8/OSM also, 80 -CO. 6) ogin

Add a comment
Know the answer?
Add Answer to:
A battery is constructed at 25ºC using the voltaic cell with initial concentrations Zn│Zn2+ (0.100 M)...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A battery is constructed at 25ºC using the voltaic cell with initial concentrations             Zn│Zn2+ (0.100...

    A battery is constructed at 25ºC using the voltaic cell with initial concentrations             Zn│Zn2+ (0.100 M) ││Ag+ (1.500 M) │Ag             How much does the cell voltage drop when 95% of the capacity (i.e., the concentration of Ag+ drops to 5% of its starting value) is consumed?             The standard reduction potentials for the two half-cells are +             Zn2+ + 2e- → Zn          Eº = − 0.76 V             Ag+ + e- → Ag Eº = 0.80 V

  • A voltaic cell is set up with one beaker containing 1.0 M Zn(NO 3) 2 and...

    A voltaic cell is set up with one beaker containing 1.0 M Zn(NO 3) 2 and a zinc electrode, and another beaker containing 1.0 M Ni(NO 3) 2 and a nickel electrode. Given the following standard reduction potentials, answer the 3 questions below: ​ Eº Zn2+(aq) + 2e → Zn(s) -0.76 V Ni2+(aq) + 2e → Ni(s) -0.23V Part a. Write out the half-cell reaction that occurs at the anode of the voltaic cell. Part b. In which direction do...

  • Consider the voltaic cell and reduction half potentials: Zn(s) | Zn 2+(aq) (0.100 M) || Ni2+(aq)...

    Consider the voltaic cell and reduction half potentials: Zn(s) | Zn 2+(aq) (0.100 M) || Ni2+(aq) (1.50 M) | Ni(s) Zn 2+ (aq)/Zn (s) E o = - 0.760 V Ni2+ (aq)/Ni (s) E o = - 0.230 V a) Sketch the voltaic cell represented with the above line notation. Label the anode and cathode and indicate the half-reactions occurring at each electrode and the species present in each solution. Also indicate the direction of electron flow (3 marks). b)...

  • What is the anode of the voltaic cell made by the combination of following half reactions?...

    What is the anode of the voltaic cell made by the combination of following half reactions? Reaction Standard Reduction Potential Zn2+ + 2e– → Zn E0 = –0.76 V Ag+ + e– → Ag E0 = +0.80 V   Question options: a. Zn2+(aq) b. Ag+(aq) c. Ag(s) d. Zn(s)

  • What is the potential of the cell involving this reaction? Zn + 2Ag+ → Zn2+ +...

    What is the potential of the cell involving this reaction? Zn + 2Ag+ → Zn2+ + 2Ag Reaction Standard Reduction Potential Zn2+ + 2e– → Zn E0 = –0.76 V Ag+ + e– → Ag E0 = +0.80 V    Question options: a. 0.84 V b. 0.04 V c. 2.36 V d. 1.56 V

  • Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and...

    Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and the cathode half-reaction is Sn2+(aq) + 2 e– → Sn(s). What is the concentration of Sn2+ if Zn2+ is 2.5 × 10−3 M and the cell emf is 0.660 V? The standard reduction potentials are given below Zn+2(aq) + 2 e− → Zn(s)    E∘red == −0.76 V Sn2+(aq) + 2 e– → Sn(s)   E∘red  −0.136 V

  • A voltaic cell represented by the following cell diagram has Ecell= 1.409 V . Zn(s)|Zn2+(1.00M)||Ag+(saturated Ag2X)|Ag(s)...

    A voltaic cell represented by the following cell diagram has Ecell= 1.409 V . Zn(s)|Zn2+(1.00M)||Ag+(saturated Ag2X)|Ag(s) What must be the Ksp of Ag2X? Use the following standard electrode potentials: Zn2+(aq) + 2e- →Zn(s) E° = -0.764 V Ag+(aq) + e- →Ag(s) E° = 0.799 V To enter your answer, multiply your Ksp by 1x109 then enter it to 2 decimal places.

  • One half-cell in a voltaic cell is constructed from a silver wire electrode in a AgNO3...

    One half-cell in a voltaic cell is constructed from a silver wire electrode in a AgNO3 solution of unknown concentration. The other half-cell consists of a zinc electrode in a 1.9 M solution of Zn(NO3)2. A potential of 1.48 V is measured for this cell. Use this information to calculate the concentration of Ag (aq). E® Zn/Zn2+ = -0.763 V Eº Ag/Ag+ = 0.7994 V Concentration = Submit Answer Try Another Version 6 item attempts remaining

  • A voltaic cell consists of a Zn/Zn2+ anode and a Ni/Ni2+ cathode at 25 ∘C. The...

    A voltaic cell consists of a Zn/Zn2+ anode and a Ni/Ni2+ cathode at 25 ∘C. The initial concentrations of Ni2+ and Zn2+ are 1.700 M and 0.120 M , respectively. The volume of half-cells is the same. Question 2 1 pts A voltaic cell consists of a Zn/Zn2+ anode and a Ni/Ni2+ cathode at 25°C. The initial concentrations of Ni2+ and Zn2+ are 1.700 M and 0.120 M, respectively. The volume of half-cells is the same. What is the concentration...

  • A voltaic cell consists of a Zn/Zn2+ half-cell and a Ni/Ni2+ half-cell at 25 ∘C. The...

    A voltaic cell consists of a Zn/Zn2+ half-cell and a Ni/Ni2+ half-cell at 25 ∘C. The initial concentrations of Ni2+ and Zn2+ are 1.80 molL−1 and 0.130 molL−1, respectively. Zn2+(aq)+2e−→Zn(s)E∘=−0.76V Ni2+(aq)+2e−→Ni(s)E∘=−0.23V A) What is the cell potential when the concentration of Ni2+ has fallen to 0.600 molL−1? B) What are the concentrations of Ni2+ and Zn2+ when the cell potential falls to 0.45 V?

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT