An empty railroad car of mass 4400 kg is being pulled beneath a grain elevator that dumps grain at the rate of 175 kg/s. If the coefficient of friction between the car wheels and the track is 0.021, what is the force needed to keep the car moving at a constant speed of 1.9 m/s 25.0 s after the grain is first dumped on the car
Points given for correct answer and explanation
Mass of Car=4400 kg
Mass of grain of car=175*25=4375 kg
Total mass=4400+4375=8775 kg
Friction force acting=mu*m*g
mu=0.021
Force required=Force of friction=0.021*8775*9.8
=1806 N
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