A 25.5-g object moving to the right at 20.5 cm/s overtakes and collides elastically with a 12.0-g object moving in the same direction at 15.0 cm/s. Find the velocity of each object after the collision. (Take the positive direction to be to the right. Indicate the direction with the sign of your answer.)
25.5-g object | cm/s |
12.0-g object | cm/s |
Suppose after collision 12g is moving with v1 and 25.5g object with v2 in same direction,
collision is elastic, so
velocity of approach = velocity of separation
20.5 - 15 = v1 - v2
v1 = 5.5 + v2 .........(i)
Using momentum conservation for this collision,
25.5 x 20.5 + 12 x 15 = 25.5v2 + 12v1
12v1 + 25.5v2 = 702.75
putting value of v1 from eqaution(i)
12(5.5 + v2) + 25.5v2 = 702.75
37.5v2 = 636.75
v2 = 16.98 cm/s ....................velocity of 25.5 g object.
v1 = 5.5 + v2 = 22.48 cm/s .........velocity of 12 g object.
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