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2- (40 pts) Using Navier-Stokes equations, in class we developed the velocity profile between two stationary infinite paralle

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(b) (a) u(y) = 4( 3P (y? - hy) Let & a us assume a strip dy thickness dy at height JU from the bottom blage The discharge fr- Now q = A x V ; where A = Total aree v = aug- velocity com) n3 = hx V alsos u(y) = 4 (P.) (g? - hy) the max. velocity is at226 ܐܓܟܐ . 1 800 x10 - 1x 106 xl 05] - ܘܥܐ ܙ - - 13 : 34 Y c . go 2 ܛܒܐܗ z4 . 55 |ܝܺܐܡ ܝ2ܐ 18 ; V - ܥܩܡܢ܂ 2 - 5 -(cܫܓ] AV : R

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