Sol:
df=n-1=5-1=4
alpha=0.05
alpha/2=0.05/2=0.025
t critical
==T.INV(0.025,4)
=2.776445105
95% confidence interval for mean
xbar-t*s/sqrt(n),xbar+t*s/sqrt(n)
8.9-2.776445105*0.9/sqrt(5),8.9+2.776445105*0.9/sqrt(5)
7.782502,10.0175
7.8<mu<10.0
ANSWER:
7.8<mu<10.0
21) 5 squirrels were found to have an average weight of 8.9 ounces with a sample...
12 squirrels were found to have an average weight of 10.2 ounces with a sample standard deviation is 0.15. Find the 90% confidence interval of the true mean weight.
10 squirrels were found to have an average weight f 9.6 ounces with a sample standard deviation is .30. Find the 95% confidence interval of the true mean weight. A) (8.67,10.53) B) (9.39, 8.81) C) (9.51, 9.69) D) (9.31, 9.89)
You measure 26 textbooks' weights, and find they have a mean weight of 60 ounces. Assume the population standard deviation is 8.5 ounces. Based on this, construct a 99% confidence interval for the true population mean textbook weight. Give your answers as decimals, to two places <u< You intend to estimate a population mean u from the following sample. 38.9 38.3 41.1 52.2 40.8 49.8 43.1 38.1 48 43.9 46 38.9 Find the 95% confidence interval. You know that the...
You measure 49 textbooks' weights, and find they have a mean weight of 59 ounces. Assume the population standard deviation is 9.7 ounces. Based on this, construct a 95% confidence interval for the true population mean textbook weight. Give your answers as decimals, to two places
a. You measure 43 watermelons' weights, and find they have a mean weight of 48 ounces. Assume the population standard deviation is 2.2 ounces. Based on this, what is the maximal margin of error associated with a 95% confidence interval for the true population mean watermelon weight? Give your answer as a decimal, to two places ± ounces b. You measure 25 watermelons' weights and find they have a mean weight of 44 ounces. Assume the population standard deviation is...
Shania loves squirrels, but she has no idea what the mean of her squirrels weight is. She takes a random sample of n=214 squirrels and obtains a 95% confidence interval for µ, the true mean weight of all of the squirrel weights in her yard – 0.8 to 1.4 lbs. Which of these is the correct interpretation of her confidence interval? A. Shania can be 95% confident that the true mean weight of the squirrels in her yard is between...
Suppose that textbook weights are normally distributed. You measure 21 textbooks' weights, and find they have a mean weight of 75 ounces. Assume the population standard deviation is 11.4 ounces. Based on this, construct a 95% confidence interval for the true population mean textbook weight. Round answers to 2 decimal places.
You measure 21 textbooks' weights, and find they have a mean weight of 43 ounces. Assume the population standard deviation is 12.6 ounces. Based on this, construct a 90% confidence interval for the true population mean textbook weight. Give your answers as decimals, to two places < μ <
You measure 48 turtles' weights, and find they have a mean weight of 72 ounces. Assume the population standard deviation is 8.1 ounces. Based on this, what is the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight.
You measure 41 turtles wroghrs and find they have a mean weight of 60 ounces. Assume the population standard deviation is 13.6 ounces. Based on this, construct a 95% confidence interval for the true population mean turtle weight.