Ho: political preference is indepedent of age
H1: political preference is not indepedent of age
Chi-Square Test | ||||||||
Observed Frequencies | ||||||||
age group | Calculations | |||||||
political preferance | 20-35 | 36-50 | older than 50 | Total | fo-fe | |||
conservative | 14 | 35 | 19 | 68 | -9.46 | 10.18 | -0.72 | |
moderate | 80 | 90 | 41 | 211 | 7.205 | 12.985 | -20.19 | |
liberals | 44 | 21 | 56 | 121 | 2.255 | -23.165 | 20.91 | |
Total | 138 | 146 | 116 | 400 | ||||
Expected Frequencies=Σrow*Σcolumn/Σ grandtotal | ||||||||
age group | ||||||||
political preferance | 20-35 | 36-50 | older than 50 | Total | (fo-fe)^2/fe | |||
conservative | 23.46 | 24.82 | 19.72 | 68 | 3.815 | 4.175 | 0.026 | |
moderate | 72.795 | 77.015 | 61.19 | 211 | 0.713 | 2.189 | 6.662 | |
liberals | 41.745 | 44.165 | 35.09 | 121 | 0.122 | 12.150 | 12.460 | |
Total | 138 | 146 | 116 | 400 |
a)
test stat=Σ(fo-fe)^2/fe = 42.31
df= (row-1)(column-1) = (3-1)(3-1) = 4
p value=0.0000 [excel fucntion: =chisq.dist.rt(42.31,4) ]
since, p value <α=0.01, reject Ho
so, there is enough evidence to reject the null hypothesis at α=0.01
Based on the results of a survey questionnaire, 400 individuals were classified as either politically conservative,...
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