Question

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A 10 eV electron (an electron with a kinetic energy of 10 eV) is incident on a potential-energy barrier that has a height equal to 13 eV and a width equal to 1.0 nm. T = e^-2alpha a alpha > > 1 Use the above equation (35-29) to calculate the order of magnitude of the probability that the electron will tunnel through the barrier. 10 _________ Repeat your calculation for a width of 0.10 nm. 10 _________

Answer 1

ct Use the below expressi on to determine the transmissi on probability 2m(V-F) Here, a is the width of the potenti al barrier and a-- Consi der V-13 eV and E-10 eV, a 1.0 nm 9k10 Y13-10 (2z) 2/9*103-10%1.6x10 6.635×10-A 0.2×10-7 Therefore, the order of magnitude is 10 Considerび= 13 eV and E = 10 eV, a = 0.1 nm 9.10 Y13-10y 0.3.10→ (2z) 2/9*103-10%1.6x10 0.110 6626x1034 0.16988x10 Therefore, the order of magnitude is 10