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2. An electron with energy E= 1 eV is incident upon a rectangular barrier of potential energy Vo = 2 eV. About how wide must

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Vo L Jhe tu ing (v-E) 1G EV -2KL e T: 2 Where (v-E) 2 m Given V= 2 eV 1 eV E or E (aheek thinif 1 hane put thas ragt correct2x 1.1X 1 32-1)x16x19 7k- 2 (40 S. 12 x 10 16 E (V-E) for - 2 k L Ta16 x1(2-1)2x S.12 xl09 L e 2 2 0 - 1. 02396 Xlo e 16-3 10 10 - 1,02396 xtoL ln 10 L 1. 02396 x(0L - 8.281 8.29 L : - 8,1x(0-l

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