Question

Solve the following with chemsitry knowledge.

QUESTIONS 1. What is the molarity of each of the following solutions? You pipet 25.00 mL of 0.355 M KCI into a 100.00 mL volumetric flask and fill to the mark a.

Answer 1

1.

Formula:-
Formula C_1V_1 = C_2V_2....(1) Where, C_1 = Initial concentration. V_1 = initial volume. C_2 final concentration. V_2 = final volume. a) C_1 = 0.355 MV_1 = 25 ml C_2 = ? V_2 = 100 ml from eq(1) we have, 0.355M times 25ml = C_2 times 100ml C_2 = 0.355M times 25ml/100ml = 0.08875M b) c_1 = 0.08875 M V_1 = 10 ml C_2 = ? V_2 = 50 ml from eq(1) we have 0.08875M times 10ml = C_2 times 50ml C_2 = 0.08875M times 10ml/50ml = 0.01775M c) C_1 = 0.01775 M V_1 = 5 ml C_2 = ? V_2 = 25 ml from eq(1) we have, 0.01775M times 5ml = C_2 times 25ml C_2 = 0.01775M times 5ml/25ml = 0.00355M 2. Different substance will absorb light at different wavelength. For a particular substance we choose the wavelength which gives maximum absorbance (for solution having higher concentration of substance from the series of solutions.) 3. Balanced molecular equation Ag(NO_3)_(aq) + 2NH_3(aq)
....(1)

Where,

C₁ = intitial concentration. V₁ = initial volume.

C₂ = final concentration. V₂ = final volume.

a)

C1 = 0.355 M V1 = 25 ml

C2 = ? V2 = 100 ml

from eq(1) we have,

b)

C1 = 0.08875 M V1 = 10 ml

C2 = ? V2 = 50 ml

from eq(1) we have

c)

C1 = 0.01775 M V1 = 5 ml

C2 = ? V2 = 25 ml

from eq(1) we have,

2.

Different substance will absorb light at different wavelength. For a perticular substance we choose the wavlength which gives maximum absorbance (for solution having higher concentration of substance from the series of solutions.)  

3.

Balanced molecular equation:-

$Ag(NO_{3})_{(aq)} + 2NH_{3} _{(aq)} \rightarrow [Ag(NH_{3})_{2}]^{+}(NO_{3})^{-}_{(s)}$

Total ionic equation:-

$Ag^{+}_{(aq)} + NO_{3}^{-}_{(aq)} + 2NH_{3} _{(aq)} \rightarrow [Ag(NH_{3})_{2}]^{+}(NO_{3})^{-}_{(s)}$

Net ionic equation:-

$Ag^{+}_{(aq)} + NO_{3}^{-}_{(aq)} + 2NH_{3} _{(aq)} \rightarrow [Ag(NH_{3})_{2}]^{+}(NO_{3})^{-}_{(s)}$

Note:-