Question

#1, #3, and #5-7 please!!!

Pre-Lab Questions 1. Write the balanced chemical equation for the formation of FeSCN2" from Fe(NO3)3-9H:0 and NaSCN. 2. In this experiment a dilute solution of 0.1 M HNO is used to maintain the ionic strength and low pH needed for the reaction to occur. How is nitric acid classified in terms of MSDS? What are some of the safety concerns regarding the handling of nitric acid? 3. Look at the procedure for making the standard solutions. What is the molar ratio of Fe to SCN in solution S4? 4. What is the max for the Absorption of FeSCN2 in 0.1 M HNO3? For the second part of the experiment, you will need a working stock solution that is approximately 0.002 M Fell Describe exactly how you will prepare a 0.002 M Fe solution from a stock solution that was made using 40.4 g of Fe(NO3):9H;O in 500 mL of 0.IM HNO). 6. In the second part of the experiment, you will collect absorbance data for a series of mixtures of Feland SCN'. Prepare a sample data table that you will need in order to complete the ICE table and make the calculation for the equilibrium constant. Given that the molar absorptivity constant for FeSCN2* is 63.7 (mg/mL)'cm'. calculate the molar concentration in moles/L of FeSCN2- in a solution with a max absorption of 0.32. Procedure Part A - Calibration Curve for Spectrophotometric Determination of FeSCN Preparing Calibration Standards for FeSCN- 1. Label six 25.00-ml volumetric flasks S1 through S6. 2. Prepare six FeSCN calibration standards (S1-S6) according to Table 1 below. Begin by delivering 4.00 mL of 0.2 M Fell solution into each of the volumetric flasks. 3. Using a micropipette, deliver the requisite amount of 0.002 M NaSCN solution to each flask according to Table 1. Fill flasks to the mark with 0.1 M HNO3 and mix thoroughly. Solution Vol 0.2 M Fe+ (mL) Vol 0.002 M NaSCN (mL) 4.00 Final Volume (mL) 25.00 25.00 SI S2 0.00 0.40 25.00 0.80 4.00 0.20 4.00 S4 4.00 S5 4.00 1.20 S6 4.00 1.60 Table 1. Standard Solutions for FeSCN2+ ion Calibration Curve 25.00 25.00 25.00

Answer 1

#1. Balanced chemical reaction ;

Fe(NO3)3.9H2O + NaSCN(aq) >>>>>>>> [Fe(SCN)]^+2(aq) + Na^+(aq) + 3 NO3^-(aq) .

Ionic equation;

Fe^+3(aq) + 3NO3^-(aq) + Na^+(aq) + SCN^-(aq) >>>>>> [Fe(SCN)]^+2(aq) + Na^+(aq) + 3NO3^-(aq)

Net ionic equation ;

Fe^+3(aq) + SCN^-(aq) >>>>> Fe(SCN)]^2+(aq) .