Question

Lab Report: Determination of Kc for a Complex Ion Formation

tube 2.00e-3 Fe3+ (mL) 2.00E-3M SCN- (mL) water (mL) initial conc. Fe3+ initial conc. SCN-
1 5.00 5.00 0 1.00e-3M 1.00E-3M
2 5.00 4.00 1.00 1.00E-3M 8.00E-3M
3 5.00 3.00 2.00 1.00E-3, 6.00E-3M
4 5.00 2.00 3.00 1.00E-3M 4.00E-3M
5 5.00 1.00 4.00 1.00E-3M 2.00E-3M

10ml of 0.200M Fe3+, 2.00ml of 0.00200M SCN-, AND 8.00ml of water results in an eq. [FeSCN2+] IN Standard Soln.:2.00E-4M

Table 3: Standard Solutions for Calibration Curve Tube Composition Blank 0.200 M Fe(NO3)3 in 1 M HNO3 1 Stock Solution (Part

Calibration Curve Data (Spectrophotometric Method, Part D) Show a sample dilution calculation for Tube Absorbance [FeSCN] (M

Could you please explain how to do one calculation of the [FeSCN2+] for the Tubes using 4ml stock solution and 1ml H2O?

The reaction that is assumed to occur in this experiment is: Fe3+ (aq) + SCN– (aq) =FeSCN2+ (aq)

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