Question

help with calculating the “initial [SCN^—]” M and the Equilibrium [Fe(SCN^2+)] M.

i have one. just not sure how to set up the equation to find the inital [SCN^-] . not sure if im calculating it correctly.

Data Manipulation and Calculations Calibration Solutions Data 1. Calculate the "Initial [SCN']" molarities for the solutions using the dilution equation CiVI=C2V2 2. Use the net ionic equation for the reaction, the ratio of [Fe3 [SCN'] used, and your knowledge of Le Châtelier's Principle to deduce the "Equilibrium [Fe(SCN)2]" molarity values. 3. Make a graph of your "Absorbance of Solution" values as a [Fe(SCN) " values. Draw a straight line of best fit" through the values (NOT a zig-zag line connecting the values!). function of "Equilibrium Data and Calculations Show All Work! Calibration Solutions Data Test Tube: 1 2 4 5 6 Volume 0.200 M Fe(NO)3, mL 10.00 10.00 10.00 10.00 10.00 10.00 Volume 0.00200 M NaSCN, mL 0 1.00 2.00 3.00 4.00 5.00 Initial [SCN'] in M Equilibrium [Fe(SCN)] in M 0 S24 Absorbance of Solution .34 52 0 .07 6 5 10.00 cro, C0200M NascNim VE 1.0 mL 10,00 5.00 4,00 C :50.0mL Plus Silver Edition EXAS INSTRUMENTS 1.078431373 lo.00z00)M1.Den 50.0 mL 0+1 002 initial ESCN 4E-5 FORMAY F3 CALC F TABLE FS Z0OM GRAPH TRACE INS DEL LIST STAT DRAW C DISTR PRGM CLEAR VARS cos F TH TAN G cos TAN 9 1w LS U 4 V 5 MEM

Answer 1

In this the initial concentration of SCN- can be calculated by multiplying the initial molarity of the solution i.e. 0.2 M by its volume that has been added and then dividing it by the total volume then i.e. volume added + 10.

1. So first part will have 0 molarity because no amount has been added.

2. In this 1 mL has been added so (1x0.2)/11

3. In this 2mL has been added so (2x0.2)/12

4. In this 3mL has been added so (3x0.3)/13

5. In this 4ml has been added so (4x0.2)/14

6. In this 5mL has been added so (5x0.2)/15