25) total Volume of solution = 20 mL
Initial Molarity of Fe3+ = 0.002 M
[M Fe3+]ini = Initial Volume * Initial molarity / Final molarity = 5.00 mL * 0.002 M / 20 mL = 0.0005 M
Similarly, [M SCN-]ini = 0.002 M * 4 mL / 20 mL = 0.0004 M
Fe3+ | SCN- | <=> | FeSCN2+ | |
I(M) | 0.0005 | 0.0004 | 0 | |
C(M) | -1.5 *10-4 = -0.00015 | -0.00015 | 0.00015 | |
E(M) | 0.0005 - 0.00015 = 0.00035 | 0.00025 | 0.00015 |
Ka = [FeSCN2+] / [Fe3+][SCN-] = (0.00015) / (0.00025)(0.00035) = 1.71 *103
PART 24) What are the units for Equilibrium Constant? A, Ms-s B) M C)Ms! D) si E) none of these. ...
Beers law solve for E3 and E4 showing work Part II. Equilibrium Constant Calculations Calculate the initial moles of Fe3+ and SCN- for solutions E2 through E6 and record these values in the table on your Data Sheet. You obtain the moles of the reactants by multiplying their molarity by the volume (in L) of their solution used. Determine the equilibrium concentration of FeSCN2+ for each of the solutions E2-E6 from your Beer’s Law plot. Using these equilibrium concentrations, the...
4. When 5.00 mL of 0.500 M Fe (NO3)3 are mixed with 5.00 mL of 0.250 M NaSCN, the following reaction occurs: Fe3+ (aq) + SCN(aq) $ FeSCN2+(aq) At equilibrium the concentration of FeSCN2- is found to be 6.00 x 10-2 M. A. Fill in the table below with the proper numerical values. (Remember to take into account the effects of dilution when calculating the initial molarity of Fe3+ (aq) and SCN'(aq) Fes- (aq) SCN (aq) FeSCN-(aq) Initial Molarity Change...
. Determination of an equilibrium constant Use the calculated absorbance values from Table 4 in Part II (y values and the best-fit line equation from Part I to calculate the [FeSCN2"), at equilibrium. Show two sets of calculations and complete Table 6 below. Sample Calculation with hypothetical values of Absorbance from Table 4 & fitted egn. from Table 3 y = mx + b (y is absorbance) 0.0620 - 2000x -0.0250 x-0.0620+ 0.0250 2000 = 4.35 x 10 с D...
values used for table 2 how do you do the Ice tables??? Experiment V. Equilibrium Constant Lab Report ( 50 pts) Calibration Curve 1. Record the absorbance for each of the standard solutions in the table below. Calculate the concentration of FeSCN)" in each of the standard solutions and record the values in the table below. Show a sample calculation (for A2) of your work in the space below the table. Solution Absorbance [Fe(SCN)" A-1 A-2 A-3 0.000 0.390 0.535...
For each equilibrium sample, calculate the initial concentrations (assuming no reaction occurred) of SCN– and Fe3+ based on the dilution factors used. Enter the absorbance values for each sample. For the standard solution, assume that, when equilibrium is reached, the [FeSCN2+]eq is equal to [SCN–]ini. Why is this a good assumption? For the equilibrium solutions, calculate the [FeSCN2+]eq (Ceq) using Eq. 4. Using Eq. 5 and 6, calculate [Fe3+(aq)]eq and [SCN–(aq)]eq for each equilibrium solution. Calculate values for the equilibrium...
can you please help me with this Data and Calculations Trial 0:29 Absorbance 0.378 Je 0.086 Trial 2 0.47 Trial 3 0.632 Trial 4 0.729 0.686 Absorbance of standard Triw. 329 0.6 6 Temperature ke [Fe(SCN) 2+]/([Fe3+] [SCN-]) Ferrag) + SCN Cag) 2 FescN2t (ag) Absorbance of standard (Trial) Temperature 0.3 Ke expression: [Fe] 0.0010 [SCN) 10.00040 [FeSCN? Jeg [Fe [SCN ] Ke value Average of Ke values Percent error (see pg 7): (Discuss this result as part of your...
Table A. Preparation of Standard solutions of FeSCN2+ 1.0 M HNO3 0.002 M 0.200 M Solution KSCN (mL) Fe(NO3)3 (mL) 0.5 5 [FeSCN2+] (mol/L)* 1 4.0x10^-5 Add 1.0 M 2 1.0 5 8.0x10^-5 HNO3 3 1.5 5 1.2x10^-10 4 2.0 5 1.6x10-4 to each to adjust the volume to 25 mL. 5 2.5 5 2.0x10-4 * Calculate the concentrations of FeSCN2+ in each beaker, assuming that all SCN-ions exist as FeSCN2+. In other words, [FeSCN2+] (in Soln 1) = [SCN-]...
Partner: Data Sheet & Calculations. Part I: For this part of the experiment assume (SCN"]= FeSCN21 Table 3: Trial % Transmittance [SCN); [Fe(SCN)?) Absorbance 2 89.9 0.00004 0.0462 0.00004 3 79.1 0.00008 0-1018 0.00012 4 66.1 10.17918 000012 5 58.3 0.00016 10.2343 o.ooola 0.00020 6 51.0 0.2924 0.00 02 apb00% Calculate the [SCN Ji and [Fe3+]; accounting for dilution using MeV. - MV., for each solution in Table 1. Show one sample calculation for absorbance, (SCN) and [FeSCN?"). Enter all...
#1, #3, and #5-7 please!!! Pre-Lab Questions 1. Write the balanced chemical equation for the formation of FeSCN2" from Fe(NO3)3-9H:0 and NaSCN. 2. In this experiment a dilute solution of 0.1 M HNO is used to maintain the ionic strength and low pH needed for the reaction to occur. How is nitric acid classified in terms of MSDS? What are some of the safety concerns regarding the handling of nitric acid? 3. Look at the procedure for making the standard...
I. Write the equilibrium constant expression, K for the following reaction Fe"(ag) FENCS(ag) SCN (ag) + CFENCS D 2. In part A of Experiment 34, it was assumed that all of the SCN added to the reaction mixture was converted to product (FeNCS). Which of the following best explains why that assumption was valid? A) The moles of Fe added equaled the moles of SCN- added. B) In part A, the SCN was the limiting reactant whereas in part B,...