Question

1. For each equilibrium sample, calculate the initial concentrations (assuming no reaction occurred) of SCN^– and Fe³⁺ based on the dilution factors used.
2. Enter the absorbance values for each sample.
3. For the standard solution, assume that, when equilibrium is reached, the [FeSCN²⁺]_eq is equal to [SCN^–]_ini. Why is this a good assumption?
4. For the equilibrium solutions, calculate the [FeSCN²⁺]_eq (C_eq) using Eq. 4.
5. Using Eq. 5 and 6, calculate [Fe³⁺(aq)]_eq and [SCN^–(aq)]_eq for each equilibrium solution.
6. Calculate values for the equilibrium constant K_c using Eq. 2.
7. Calculate the best value for K_c.
8. If equal quantities of Fe³⁺, SCN^–, and FeSCN²⁺were mixed in a solution, which species would be present in greatest concentration at equilibrium? Why?
   Laboratory 5: Determination of Kc for FeSCN2+ Data Table 1 Laboratory 5: Determination of Equilibrium Constant Table 1 provides an organization for performing the calculations on the equilibrium solutions. 1. For each equilibrium sample, calculate the initial concentrations (assuming no reaction occurred) of SCN and Fe3+ based on the dilution factors used. 2. Enter the absorbance values for each sample 3. For the standard solution, assume that, when equilibrium is reached, the [FeSCN2+leg is equal to [SCN-lini Why is this a good assumption? 4. For the equilibrium solutions, calculate the [FeSCN leq (Ceq) using Eq. 4 5. Using Eq. 5 and 6, calculate Fe3 (aqleg and [SCN-(aqlleq for each equilibrium solution. 6. Calculate values for the equilibrium constant Kc using Eq. 2 7. Calculate the best value for Ke 8. If equal quantities of Fe3+, SCN-, and FesCN2twere mixed in a solution, which species would be present in greatest concentration at equilibrium? Why? Table 1: Solution Composition for Iron-Thiocyante Solutions Standard Equilibrium Solutions 2 4 18.0 Volume 0.200 M Fe+, mL Volume 0.0020 M Fe3, mL Volume 0.0020 M SCNT, mL Volume water, mL Fe3 lni M (Calculated) SCN lini M (Calculated) Absorbance FeSCN2 leq, M Fe3 leq, M (Calculated) SCN leq: M (Calculated) Kc 5.0 1.0 4.0 5.0 2.0 3.0 5.0 3.0 2.0 5.0 5.0 5.0 0.0 2.0 4.0 094 466 .593 1.007 1.221
   

Answer 1

limiting reagents concept taken into count.

OO lo Mil so.ou 4 (o.oto.О.004) (0.004-о.ooリ . :006 0.002 서 La-メ) b-2x ERu.ee, br,'뻐 [Scw] ar こ0 Milimoly turned [fe(ceu),j, = of o.oo2ndu X X = o.oo4. Mie'm.dad | Ebum. (10+ux) [re(sen27 (10-х) し10-2x) fe (scn o.oo 2, M,,me k Xdua, ith - greskes of ll, a initist 0.001 0.002서 s mL (b-2x x 0.002 1 10.0100.000 ooos

here SCN- is the limiting reagent. here 2 moles of SCN- taken for reaction , hence half of the concentration of [SCN-] /2 will be the amount of product.

please find attached file for detailed information