Question

Experiment V. Equilibrium Constant Lab Report ( 50 pts) Calibration Curve 1. Record the absorbance for each of the standard solutions in the table below. Calculate the concentration of FeSCN)" in each of the standard solutions and record the values in the table below. Show a sample calculation (for A2) of your work in the space below the table. Solution Absorbance [Fe(SCN)" A-1 A-2 A-3 0.000 0.390 0.535 0.713 0.835 0.898 1. 102 11.0x104M 1.48104 M 1.8 X 10-4 M 22 x 10-4 M 268104 M 3.0 x104 M A-5 A-6 II. Determination of the equilibrium constant 1. Record the absorbance values for each of the equilibrium solutions in part II and calculate the [Fe(SCN) , concentration for each of the solutions using the obtained calibration curve in part 1. Show your work in the space provided below. Solution Absorbance [Fe(SCN) B-1 B-2 B-3 3-4 0.114 0.260 0.359 0.537 0.623 1.82 X 10-4 3.648164 5.45 8 10 4 7.24 8104 9.09x104 B-5 2. Determine the equilibrium concentrations of each of the reactants and products in solution B-1 using the table provided below (ICE table). Fill in all blank values [Fe] (SCN) [Fe(SCN) Initial Concentration Change in Concentration Equilibrium Concentration 3. Determine the equilibrium concentrations of each of the reactants and products in solution B-2 using the table provided below (ICE table). Fill in all blank values Fes [SCN) [Fe(SCN)?") Initial Concentration Change in Concentration Equilibrium Concentration

values used for table 2

how do you do the Ice tables???

Answer 1

- Date astion Curstion Dilmarch 2020 How do you We know that Equilibaien you complete the ICE Tables that to form the fecsen)]" complex, Reaction goes like this: 7. Reaction geas + Fets laq) Ser cap = [Fe (SCN) comples Fels (Red colored) a First of Collboni all we have to ef [fecsCA)?? for u prepovu a standard por determinining the absoslancer prepare delers Equiübrien an Equiles for a in tables " happenira 6 How to Reaction particular Analyse what is we have to foom solucións- Vnitial change in Equilibreurs conch conc. concn Case I: LFor solution B-{] Total volume of Holution (V) - 4 me ( Vol. op fe' } vol of San ' + Vol.of H202 A As the data is geen bu table 11. (A) { Initial concentration of fet 3 (0.002M) taken 5.0ml en a isto test tube ) Total mmoles of Fet3 Treti’ally present Total volume of Sovetion 9.09 x264 w Ime 1182X164M Initial cont. Fet3 -7 mmoll 0.002MX 5.0mL), at t=0 10.002M) Initial. conc. of SCN - 10.002M X tome) - at t=0 (0.002M) Fet3+ Sc = FecSCH) + 8.09x16M) (182X169M) - (9.09816420) (1.82X169_74 . 84 -> at t- 0 At Sabimletegein cone? at Egbm. ay for By is abready mentioned in Table :0) data 24 → 187 X10'M → So now we can fill the Ice 1 the icooble cam şicanner PORNO

peut value of 24 ad fùl Hai blenzk for B-1 volution Cententzen (4) (SCN) [Fe(scn)]2+7 9109x104M 1.82X10%M 0.014 -X=> -1082x16M -=> -1.82816?r +2,718 exity 19.09X304- Equilibrium 121'89X1041-7-82X154) 77. 2747 X10''M L -0.0M 1.82x10% Vitae chango duralarly for volution 0-2 -> Equilibruina cone. = 3.64x10 mg Totay' voleurs (V) GY? - 77774 1X2) ha cox of pot iz Totu mmolls of Fet 3 gnitially pressit Total Vol. of Solliton (V) - 0.002M Y 5.0m - 9.09X164M 11m initial conc" of SCN - To tie m: 92016 M. SCN Initially presunt Tote Velli cy Soin (V) >> 0.002M X 2:0 nu =) 3164x169M 11.9726 Fet aq) + Senilag) = Feiben)) attro Initially gooxoling at Sabh (9:09x098_222)M (3.648109 -x2M 2M w as he is given as 3.648 154m in table 1).(1) "Put value of xy + cómplete the ICE table for 3-2 Solution. cone fet3 ScH I felson)]2+ Tribal 9.09 x104 M 13:62x15%my Dom for B-2 -22 -X2 change Spuition -3.64X16 "My 13). -3:69x1049) >> 3.64X10M SERIES Equilibrium Svi 5.451104 I oom | 3.64X154 M Innedy