Question

In test tube 10, the following volumes of solutions are combined: 3+ 0.0025 M Fe (mL) 0.0025 M SCN (mL) 0.1 M HNO3 (mL) 3.0 3

Any help with this ICE table is very much appreciated! Thanks.

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Answer #1

initial Fe3+ = millimoles / total volume

                       = 0.0025 x 1 / (1 + 3 + 3 )

                        = 3.57 x 10^-4 M

initial SCN- = millimoles / total volume

                   = 0.0025 x 3 / (1+3+3)

                        = 1.07 x 10^-3 M

equilibrium Fe3+ = 3.57 x 10^-4 - 0.0000462

                              = 3.11 x 10^-4 M

equilibrium SCN- = 1.07 x 10^-3 - 0.0000462

                             = 1.02 x 10^-3 M

In test tube 10, the following volumes of solutions are combined: 3+ 0.0025 M Fe (mL) 0.0025 M SCN (mL) 0.1 M HNO3 (mL) 3.0 3

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