Determine the energy needed to change a 0.35 kg block of ice at 0 ∘C into water at 23 ∘C. The heat of fusion for water at 0 ∘C is Lf = 3.35×105J/kg. The specific heat of water is c = 4180 J/kg⋅∘C.
Heat required, Q = m[Lf,ice + CwΔT]
=> Q = 0.35 * {(3.35 * 105) + [4180 * (23 - 0)] } = 150899 J
Determine the energy needed to change a 0.35 kg block of ice at 0 ∘C into...
When 1.4 × 105J of energy is removed from 0.9 kg of water initially at 20 ∘C will all the water freeze? The heat of fusion for water at 0 ∘C is Lf =3.35×105J/kg. The specific heat of water is c = 4180 J/kg⋅ ∘C. How much remains unfrozen?
The energy needed to convert 2 kg of ice at -10 °C to water at 10 °C will be { Constants Given: Specific Heat of Water = 4186 J/kg ºc, Specific Heat of Ice = 2100 J/kg ºc, and Latent Heat of Fusion = 3.33 x 105 J/kg. }
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014 10.0 points How much energy is required to change a 35 g ice cube from ice at -12°C to steam at 111°C? The specific heat of ice is 2090 J/kg.° C, the specific heat of water is 4186 J/kg.° C, the specific heat of stream is 2010 J/kg.° C, the heat of fusion is 3.33 x 10° J/kg, and the heat of vaporization is 2.26 × 106 J/kg. Answer in units of J
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