Two kilograms of ice at 0 C melts to water at 0 C, and then is heated to a temperature of 40 C. What is the change in entropy? You may assume the latent heat of fusion and specific heat for water is 3.35 x10^5 J/kg and 4186 J/KgK, respectively.
Solid ice melts at 0 °C and has a latent heat of fusion of 333 kJ/kg. How much heat is required to first melt 0.02 kg of ice into water at 0 °C, and then increasing the temperature of the water from 0 °C to 16.6 °C? (C=4186 J/kg.Cº] Heat of fusion Le Water (all liquid) Water and ice Ice at 0 °C water at 0 °C Answer: J kJ Next page Online Quizlenlaces the crada oficinss. Send message
01) A solid that has a latent heat of fusion Ly melts at a temperature 7. a) What is the change in entropy of this substance when a mass m of the substance melts, b) Estimate the value of the change in entropy of an ice cube of mass 30g when it melts. (Latent heat of fusion of ice is 3.33 x10 J/kg.)
Calculate the change in entropy when 65 g of ice at 0 °C melts to water at 0 °C? The heat of fusion is 3.34x10 J/kg.
Calculate the change in entropy when 55 g of ice at 0 ℃ melts to water at 0 ℃? The heat of fusion is 3.34x10 5 J/kg.
The temperature of 2.26 kg of water is 34 °C. To cool the water, ice at 0 °C is added to it. The desired final temperature of the water is 11 °C. The latent heat of fusion for water is 33.5 × 104 J/kg, and the specific heat capacity of water is 4186 J/(kg·C°). Ignoring the container and any heat lost or gained to or from the surroundings, determine how much mass m of ice should be added.
The temperature of 2.7 kg of water is 34° C. To cool the water, ice at 0° C is added to it. The desired final temperature of the water is 11° C. The latent heat of fusion for water is 333.5 × 103 J/kg, and the specific heat capacity of water is 4186 J/(kg·C°). Ignoring the container and any heat lost or gained to or from the surroundings, determine how much mass m of ice should be added. m = kg
How much heat is required to change 456 g of ice at -20.0Degree C into water at 25.0Degree C? specific heat of water = 4186]/(kg-K); specific heat of ice = 2090 J/(kg.K) and latent heat of fusion of water = 33.5 times 10^4 J/kg.
Calculate the heat required to raise the temperature of gm of ice at -25˚C to 70˚C. (Ice has a specific heat of 2100 J/(kg K),the latent heat of fusion for ice is 334,000 J/kg, specific of water is 4186 J/(kg K) and Melting point of ice = 0˚C). Units are kJ.
In the mixing device the slurry (mixture) of ice and water at temperature 0°C is mixed with water at temperature 20 C. The flow rate of the slurry (water + ice) is 2 kg/s and flow rate of the warm water is 4 kg/s. (a) Determine the mass flow rate of the ice, if the outlet temperature is 1°C and system is perfectly insulated. (b) Determine entropy generation rate in the perfectly insulated system. Specific heat of water is 4.19...
A 197 g cube of ice at 0◦C is dropped into 1.4 kg of water that was originally at 78◦C. What is the final temperature of the water after after the ice melts? The latent heat of fusion of water is 3.33 × 105 J/kg. Answer in units of ◦C.