You are standing in front of a Jens that projects an image of you onto a...
A photographic slide is to the left of a lens. The lens projects an image of the slide onto a wall 6.01 m to the right of the slide. The image is 84 times the size of the slide. 1) how far is the slide from the lens 2) is the image erect or inverted 3) what is the focal length of the lens 4) is the lens converging or diverging
3. Figure shows an object and its image formed by a thin lens. (a) What is the focal length of the lens and what type of lens (converging or diverging) is it? (b) What is the height of the image? Is it real or virtual? Draw a principal-ray diagram showing the formation of the image. -35.0 cm- Optic Object 15 Lens El crn Image 4. Figure shows an object and its image formed by a thin lens. (a) What is...
My answer is wrong. Please help. B Review You are standing 0.50 m in front of a lens that projects an image of you onto a wall 1.7 m on the other side of the lens. Part A What is the focal length of the lens? Express your answer in meters. IVO AO ? f = 0.26 m
A 4.0 cm tall object is 5.0 cm in front of a diverging lens with a focal length of -6.0 cm. A converging lens with a focal length of 6.0 cm is located 8.0 cm behind the diverging lens. (As viewed from the side, from left to right, the sequence is object - diverging lens - converging lens - observer. Rays then travel from left to right through the system.) (a) Use ray tracing to draw image 1 and image...
3. The design for an optical system requires an virtual image to be created in front of the objective lens at a distance of 3.20 cm when the object is only 1.00 cm in front of the lens. (a) Should the lens be a converging or diverging lens? (b) What should the focal length of the lens be? (c) Draw a (somewhat to scale) ray diagram showing the lens, object, and image,
PHYS 203 Name: Ray Tracing Name: Work in pairs. Turn in one copy per pair Part A: Ray Tracing (18 pts) For each of the following situations, draw the three principle rays and find the image. Measure, f.p. q. h and h and label them below (1 "large box" 1.0 cm). Indicate whether the image is: - real or virtual upright or inverted - enlarged or reduced - in front or behind the mirrorlens No pens allowed. Draw this in...
An object of height 3.6 cm is placed at 24 cm in front of a diverging lens of focal length, f = -18 cm. Behind the diverging lens, there is a converging lens of focal length, f = 18 cm. The distance between the lenses is 5 cm. In the next few steps, you will find the location and size of the final image. Where is the intermediate image formed by the first diverging lens? Image distance from first lens...
1. When a dime is placed 3.5 cm in front of a lens, it forms an upright image that is 2.5 times as large as the dime. [Note: It is very important in these calculations to keep track of the (+/-) sign of every variable] What is the image distance from the lens? Is the image on the same side as the coin or on the other side of the lens? 5pts) a) b) What is the focal length of...
A converging lens with a focal length of 12.0cm forms a virtual image 8.00mm tall. Image is 17.0cm from the lens. Calculate (a)the position of the object, (b)magnification of the lens, (c)height of the object. (d)Is the image upright or inverted? (e) Are the object and image on the same side or opposite sides of the lens? (f) Draw ray-diagram
An object of height 3.6 cm is placed at 24 cm in front of a diverging lens of focal length, f = -18 cm. Behind the diverging lens, there is a converging lens of focal length, f = 18 cm. The distance between the lenses is 5 cm. In the next few steps, you will find the location and size of the final image. Where is the intermediate image formed by the first diverging lens? Image distance from first lens...