14. -1 points BerCP 11 1.8.P.047. A high fountain of water is located at the center...

Question

Question

Answer 1

Answer #1

since the fountain in circular shape , the circumference is

S= 2 pi r

r = S/ 2pi = 13/2 pi = 2.07 m

from the figure

tan theta = h/r

h = r tan theta = 2.07 m tan 55 =2.95 m

Answer 2

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