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Please answer both questions fully because I am uncertain on what I did wrong, thanks!Incorrect Question 1 0/1 pts What is the E* (the biological standard half potential) for the reaction given below: NAD (aq) + H+ (aq) + 2e-→ NADH(aq) Ere,--0.099V -0.0990 Incorrect Question 2 0/2 pts What is the standard half cell potential (E°) for the reaction given below? (hint: we didnt solve for this number in the video) pyruvate (aq) + 2H+ (aq) + 2e-→ lactate (aq) Ere,--0.190V 0.1900

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Answer #1

NAD^+ (aq) + H^+ (aq) + 2e^- -> NADH(aq)/H^+ E^0 = -0.320V

Pyruvate (aq) + 2H^+ + 2e^- ----------> lactate (aq) E^0 = -0.190V

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