Question

Three circular, parallel-plate capacitors with different geometries are each filled with a different dielectric material. The plate radius r. plate separation d, and dielectric material for each of the three capacitors, C, C2, and Cz, are provided in the table. Capacitor Dielectric C 14,3 x 10-3 m 4.75 x 10-6m C2 13.9 x 10-'m m 41.6 x 10-6 m C 8.32 x 10-m 15.6 x 10-6m indium antimonide (InSb) Order the capacitors by their capacitances, from highest to lowest. The dielectric constant x for each material is listed in the second table. air diamond Highest C: Material Air Paper Glass Diamond Porcelain Gallium Arsenide (GaAs). Germanium (Ge) Indium Antimonide (InSb) 1.00 3.50 4.50 5.50 7.00 13.2 16.0 C 17.7 Сі Lowest

Answer 1

answer=the order of capacitance from higher to lower is C3>C1>C2

capacitance C= $\varepsilon$ A/d ..........A= area of plate d= distance between the plate

$\varepsilon$=a=bsolute permittivity =$\varepsilon$_r$\varepsilon$₀     $\varepsilon$ ₀ = a constant =8.85x10^-12

so capacitance C= $\varepsilon$ _r$\varepsilon$₀A/d

C1 = $\varepsilon$ ₀x1x($\pi$0.0143²)/4.75x10^-6 =135.24 $\varepsilon$ ₀Farad

C2=$\varepsilon$₀x5.5x($\pi$0.0139²)/41.6x10^-6=80.25 $\varepsilon$ ₀ Farad

C3=$\varepsilon$₀x17.5x($\pi$0.00832²)/15.6x10^-6=243.955$\varepsilon$₀ F

so the order of capacitance from higher to lower is C3>C1>C2

here