f n=450 and p' (p-prime) = 0.06, construct a 99% confidence
interval.
Give your answers to three decimals.
< p <
Solution :
Given that,
n = 450
=0.06
1 - = 1 - 0.06 = 0.94
At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
Z/2 = Z0.005 = 2.576
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 2.576 * (((0.06 * 0.94) / 450) = 0.029
A 99 % confidence interval for population proportion p is ,
- E < P < + E
0.06 - 0.029 < p < 0.06 + 0.029
0.031< p < 0.089
The 99% confidence interval for the population proportion p is : ( 0.031< p < 0.089)
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