2. [2] If the velocity at time t for a particle moving along a straight line...
The velocity of a particle moving along a straight line is given by v = 0.2s1/2 m/s where the position s is in meters. At t = 0 the particle has a velocity v0 = 3 m/s. Determine the time when the particle’s velocity reaches 15 m/s and the corresponding acceleration. Ans: 600 s, a = 0.02 m/s2
A particle moving along a straight line has an acceleration which varies according to position as shown. If the velocity of the particle at the position x = -6 ft is v = 7 ft/sec, determine the velocity v when x = 13 ft. a, ft/sec2 -6 0 0 11 13 x, ft -5
A particle moving along a straight line has an acceleration which varies according to position as shown. If the velocity of the particle at the position x = -4 ft is V-6 ft/sec, determine the velocity v when the acceleration is zero. (Note: there are several instances when acceleration is zero). a, see Sude=adso r -) = area under as curve)
4. A particle is moving along a straight line such that its velocity is defined as v -5s2 m/s, where s is in meters. If s 2 m when t0, determine the particle's velocity and acceleration as functions of time.
2. (8 points) Suppose a particle is moving in a straight line with velocity v(t) = (x + 1)2 – 2 meters per second, with an initial position s(0) = 8 meters. Find the total distance traveled by the particle after 9 seconds. Round to the nearest hundredth.
11. Suppose the position function of a particle moving along a straight line is given s(t) = t3 - 3t2 + 8, where s is in meters and t is in seconds. Include units in your responses. (a) How far has the particle traveled in 1 second? (b) What is the velocity of the particle at 1 second? (c) What is the acceleration of the particle at 1 second? (d) is the particle speeding up or slowing down or neither...
Chapter 2, Problem 2/024 Multistep A particle moving along a straight line has an acceleration which varies according to position as shown. If the velocity of the particle at the position x when 10 ft. -3 tis v 4 ft/sec, determine the velocity a, ft/see? 10 --- Part 1 Calculate od a, ft/sec 10- Part 1 Calculate adx. a, ft/sec Answer: adx the tolerance is +/-29 Click if you would like to Show Work for this questions Open Show Work
1. (10 pts) A particle moving along a straight line decelerates according to a -kv. This represents a drag-induced deceleration. Determine: a) velocity v as a function of time t b) position s as a function of time t c) velocity v as a function of position s At time t-0, the initial velocity is vo and position is s 0
The velocity of a particle, which moves along a straight line, is given by 62r m/s . The particle is at the position x3 when 0s. Find the position x, velocity S, and acceleration , when t-4s. (2 points) 1. 3/2
The velocity of a particle moving in a straight line is given by v(t) = 2 + 2. (a) Find an expression for the position s after a time t. s(t) = + C (b) Given that s = 3 at time t = 0, find the constant of integration C. C = 1 Find an expression for s in terms of t without any unknown constants. HINT [See Example 7.]