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5. For z, w E C, show the following identities. (a) z + w = z + W (b) zw = zw (c) |zw| = |2||w (d) () = 1 where w #0 (e) [2|

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5 @ take take zz xetiye a. and airy, ER W = 22 tiy te and N21 GER * 2+W = (21 +82.) + i[4,482) ► 2+W = (21 +22) - (4tY2) -O t* Zw= (2487 - 9,82]+ i (asy + xya) * ZW = (2,22-Y,02) -; (224, +242) Again zaatiy * z = 24-iy, W = xotiy W = r2-ig, o So Zw =teno * , 24 ษ + N P1 = (-1%) + (12) ไ) * 1 2 +3 - 2 พ.ศษ + ม ะ มหาร - VX5 + +2 ฯ **** = / 41% ++ * +75 ” 5 N 28 (+2) + %(+/-)I take г. Мама - z=24tiy, Eq, ay, EIR - W = xgtigel a2, YzER wzo = myring . (Where wto] dariya :(4+141) (22 -142) (22+1Y2) (2 - - (47, +97») -і» аті я *, T2W ZO a 25* 1* * *° ) С», y+977) — 1( x — 4) 17-9. — (0) Г. N +о, % ++) So by 0 and we get ()Izin o claim izhl z lzin, whore h in negative or a possitive integer case-1 for possitive integer we will prove Izl=/zlu byCase I firstly we prove izita lzl, where ato xtiy So, take z=2 tiy to So Izl= vartyr 17 a va hay 1714- Vatayz -- Again 2 = 1

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