Question

1. The management at an environmental consulting firm claims the mean weekly salary is $275 with a standard deviation of $34.10.

1. If we want to address the question “If management’s claims are true, what is the probability that an individual worker would make an average weekly salary less than $264.50?”, write the probability statement.

2. If we want to address the question “If management’s claims are true, what is the probability that an individual worker would make an average weekly salary less than $264.50?”, what is the probability? Be sure to show how you calculated your probability.

3. If we want to address the question “If management’s claims are true, what is the probability that a group of 27 workers would make an average weekly salary less than $264.50?”, write the probability statement.

4. If we want to address the question “If management’s claims are true, what is the probability that a group of 27 workers would make an average weekly salary less than $264.50?”, what is the probability? Be sure to show how you calculated your probability.

Answer 1

Ansuxs: Assuming nålmal shistribution) P(XC 2645) Namal distribution, 1-275, 6:34:1, he convert this to standard nemal using 2. -0.307918-031 z. 9645-(295) 34 1 PLZ2-031) = Area to the left of -031 0-373. 031 PCX <864 5) = P(Z 2-031) = 0 3783[from z-table) P(Z <-0-31): ina Z-table having area to the left of 2, docate.0.3 in the left most colunin, Move awon the law to the light under coloumn 0.01 get value 0.3763 cs Scan P(x4,2645) 0.3783= 37.834 Calescence