Suppose a current of 0.810 A flows through a copper wire for 30.0 minutes. Calculate how...

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Answer #1

CWhere tiR in pecord Q- Jxナ 3 X60 See (オ= 30 min 0. 810 X 30X60 oelec tron no Change on electron 1458 1.6X1019 19 911-25 X10

Answer 2

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