Question

Given the following partial code, fill in the blank to complete last node. (don't forget the semicolon) class Node { public Object data = null; public Node next = null; Node head = new Node(); // first Node head.next = new Node; // second Node head.next.next = new Node: // third node head.next next next = new Node: // fourth node

just a normal linked list

Answer 1

Answer to your question is:

head.next.next.next.next=NULL; //Last node

Explanation: Following Program is giving correct output (Here i am using turboc++ compiler so i write - > in place of . dot )

#include <stdio.h>
#include<conio.h>
class Node
{
public: int data;
public: Node *next;
} ;
main()
{
clrscr();// to clear the screen
Node *head =new Node(); //First node
head->data=1;
head->next =new Node();    //second node
head->next->data=2;
head->next->next =new Node(); //third node
head->next->next->data=3;
head->next->next->next=new Node(); //Fourth node
head->next->next->next->data=4;
head->next->next->next->next=NULL;

printf("\n First node : %d ",head->data);
printf("\n Second node : %d ",head->next->data);
printf("\n Third node : %d ",head->next->next->data);
printf("\n Fourth node : %d ",head->next->next->next->data);

}

Output:

First node : 1 Second node : 2 Third node : 3 Fourth node : 4 -