A converging lens with a focal length of 70.0cmforms an image of a 3.20-cm-tall real object that is to the left of the lens. The image is 4.50cm tall and inverted.
c-) How much to the left of the lens is the object?
Express your answer with the appropriate units.
A converging lens with a focal length of 70.0cmforms an image of a 3.20-cm-tall real object...
A converging lens with a focal length of 8.00 cm forms an image of a 5.60-mm-tall real object that is to the left of the lens. The image is 1.40 cm tall and erect. a) Where is the object located? Follow the sign rules. (express answer with appropriate units) b) Where is the image located? Follow the sign rules. (express answer with appropriate units)
A 15-cm-focal-length converging lens is 18 cm to the right of a 7.0-cm-focal-length converging lens. A 3.3-cm-tall object is distance L to the left of the first lens. Part A For what value of L is the final image of this two-lens system halfway between the two lenses? Express your answer to two significant figures and include the appropriate units. Part B What is the height of the final image? Express your answer to two significant figures and include the...
1 A converging lens with a focal length of 12.2 cm forms a virtual image 7.9mm tall, 11 2emto right of the lens. a. Determine the position of the object. b. Determine the size of the object. Is the image upright or inverted? Are the object and image on the same side or opposite sides of the lens? c. d. 2 You want to use a lens with a focal length of magnitude 36cm with the image twice as long...
A 4.0 cm tall object is 5.0 cm in front of a diverging lens with a focal length of -6.0 cm. A converging lens with a focal length of 6.0 cm is located 8.0 cm behind the diverging lens. (As viewed from the side, from left to right, the sequence is object - diverging lens - converging lens - observer. Rays then travel from left to right through the system.) (a) Use ray tracing to draw image 1 and image...
A converging lens with a focal length of 87.0 cmcm forms an image of a 3.35 cmcm -tall real object that is to the left of the lens. The image is 4.75 cmcm tall and inverted. Part A Where are the object and image located in relation to the lens? Express your answers in centimeters separated by a comma. |s||s|, |s′||s′| = nothing cmcm SubmitRequest Answer Part B Is the image real or virtual? Is the image real or virtual?...
A 2.0 cm tall object is placed 10.0 cm in front of converging lens of focal length 8 cm. What can you say about the image formed by the lens? de the image is real, magnified and inverted the image is virtual, diminished and inverted O the image is virtual, magnified and upright the image is real, magnified and upright the image is real, diminished and inverted
A 1.0-cm-tall object is 65 cm in front of a converging lens that has a 25 cm focal length. Part A Calculate the image position. Express your answer with the appropriate units. Enter positive value if the image is on the other side from the lens and negative value if the image is on the same side. Part B Calculate the image height. Express your answer with the appropriate units. Enter positive value if the image is upright and negative...
A converging lens with a focal length of 6.50 cm forms an image of a 3.80 mm -tall real object that is to the left of the lens. The image is 2.10 cm tall and erect. Where are the object and image located? in cm
A small object is placed 25.0 cm from a converging lens of focal length 40.0 cm. The object is to the left of the lens. Where is the image? A- 17cm to the right of the lens B- 25cm to the left of the lens C- 17 cm to the left of the lens D-25 cm to the right of the lens E-67cm to the right of the lens F-67 cm to the left of the lens A small object...
A converging lens with a focal length of 4.9 cm is located 20.9 cm to the left of a diverging lens having a focal length of -11.0 cm. If an object is located 9.9 cm to the left of the converging lens, locate and describe completely the final image formed by the diverging lens. a) Where is the image located as measured from the diverging lens? b) What is the magnification? c) Also determine, with respect to the original object...