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Review Part A A 2.6 kg object initially at rest at the origin is subjected to the time- varying force shown in (Figure 1). Wh

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Answer #1

Solution)

We know,

Force, F=ma

So,

a=v/t

Therefore,  F=mv/t

Conclusively, Ft=mv

Hence, area under graph = mv

area = 1/2*6*3=9

Hence,

9=mv

So, speed, v=9/2.6 kg

v=3.46 m/s (Ans)

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