Question

2. (25 points) Compute the positive and negative reinforcement of the central portion A-B of the one- way slab shown in Figure 2. You can use the simplified moments given by the ACI 318 code as we did in other problems. Assume that the slab thickness is adequate. L = 13 ft f'c = 4,000 psi, fy = 60,000 psi Beams i Top View 2xL -5@14 Wu = 0.28 kip/ft? Loin. - - - 12 in. 12 in. Figure 2

Answer 1

2) رانا تندا. Tone lan sah Ditirur Panel! O sung AC moment cufficients @L): 131–12! (2 1. fc = Akse, fy= boksi Iittero Pánc Slab thick ness is gwen - 6 Central Poster AB WS i + Wula2 -7-5251 © Leading joy Shaabasta - is guen/Shain as we=0:28 kl ft? ( tis assumed A s (factoral loading that it includes Reinforcement a sleb weight) 4. Postüne Manent at Cat Wushan? 4 0:28x (12) (miel spün) = 2:52 Kft 08 Asmidspan the = 2.52-=0:12 in ACI Specifiés As jminimeans= 318'bid fy Sunce Asmin -314000 x12x5:25= 0.20 S60, ow As tve, So pomide Astue=0.20m m? Useig #4 baus, Spaling = 0.24/12- 12:00 5-re moment at A&B = 6) 0:28X12 = 3:676f6; As = 36750:17 Sinice As ve=017 in tisk Asmen=0i Zain proide Asup=0:2010 thesis #4 baus spauíp=0:20 42= 12dcl 4X525 . . - - .. . ICP . . S - - ad