Question

Part 2 of 2 Required information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. The motion of an oscillating flywheel is defined by the relation 0 = 20e-11/6 sin4nt, where is expressed in radians and t in seconds. The value of 00=1 rad. 714 points Skipped eBook Hint Print References Determine the angular coordinate, the angular velocity, and the angular acceleration of the flywheel when t=. The angular coordinate is The angular velocity is C The angular acceleration is C rad. r ad/s. r ad/s2.

Answer 1

Given O= 0.7 16 Sin (unt) , o-rrod Angular Cordinate at t-4 -77t O=one 0=1 + 6 sincutit) Sin Cuts) O=1x0 « Sin (hta) Angular velocity at ta -71 W= do = d (o e Sin (unit) dt w=0[-7. ce ne sonbyt) + 2. Endleihe).u1) / w=1[. et omfamu) 4 eco (otsa).) w=1[040] wa orod/

Angular accertation at t=2 azd (4.ve [ 70 concunt) + 476056000) <= @of-zm. [ 79. grbome) + 4 c) (171)] ter (-741-60(471) 4TI + LT . A -Sincutit) La vFz9.2 mm [-quan(um) + uti Coslenia)] té 749 (-701 CO) (411_) -4,71 +471 44,77 6 sorkun)