P( 0in ) = 0.1 ; P( 1in ) = 0.5 ; P( 2in ) = 0.4
P(0out | 0in ) = 0.1 P(0out | 1in ) = 0.3 P(0out | 2in ) = 0.1
P(1out | 0in ) = 0.8 P(1out | 1in ) = 0.3 P(1out | 2in ) =
P(2out | 0in ) = P(2out | 1in ) = P(2out | 2in ) = 0.75
A. 1. P(2out | 0in ) = 1 - ( P(0out | 0in ) + P(1out | 0in ) ) = 1 - (0.1 + 0.8) = 1 - 0.9 = 0.1
2. P(2out | 1in ) = 1- ( P(0out | 1in ) + P(1out | 1in ) ) = 1 - ( 0.3 + 0.3) = 1 - 0.6 = 0.4
3. P(1out | 2in ) = 1 - (P(0out | 2in ) + P(2out | 2in )) = 1 - (0.1 +0.75) = 1 - 0.85 = 0.15
B. P(1out) = P(1out | 0in ) * P(0in) + P(1out | 1in ) * P(1in) + P(1out | 2in ) * P(2in)
= 0.8 * 0.1 + 0.3*0.5 + 0.15*0.4
= 0.08 + 0.15 + 0.06 = 0.29
C. P(0out) = P(0out | 0in ) * P(0in) + P(0out | 1in ) * P(1in) + P(0out | 2in ) * P(2in)
= 0.1 *0.1 + 0.3 *0.5 + 0.1*0.4
= 0.01 + 0.15 + 0.04 = 0.2
P(2in U 0out ) = P(2in | 0out ) * P( 0out ) = P(0out | 2in ) * P(2in)
Therefore,
P(2in | 0out )
=
=
= 0.04 / 0.2 = 0.2
D. P(1in |
0out ) =
=
= 0.15/ 0.2 = 0.75
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uestion One- Dmensional Parabofe :Het Equor Consielertue PDE for o xi るt tle ital concition anol t boudy conditions Solue the porobohc PbE usmg Exphet fot word Euler on o Cront-Nicholsen meods
ou -757165 uestion 3 An electric field, E, has a magnitude of 340 N/C and is directed at an angle of 55 deg relative to the +x axis. Calculate the x-component of the electric field to 2 decimal places. Answer 7.52 x (195.02) N/C Question 4 0/2 poir An electric feld, E. has a magnitude of 620 N/C and is directed at an angle of 60 deg relative to the x axis. Calculate the y-component of the electric field to...
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8, (10 pts) Show that given a directed graph G = (V,E) already stored in adjacency matrix form, determining if there is a vertex with in-degree n - 1 and out-degree 0 can be done in O(n) time where n is the number of vertices in V.
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all steps with arrows and lone pairs.
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