Question

Chapter 3, Problem 3/079 The spring of modulusk - 600 N/m is stretched a distance d = 44 mm when the mechanism is in the position shown. (a) Calculate the force Pmin required to initiate rotation about the hinge axis BC, and determine the corresponding magnitudes of the bearing forces which are perpendicular to 8C (b) What is the normal reaction force at Dif PP/2? 88 mm 42 mm 136 mm * = 600 N/m 45 mm 150 mm 42 mm mm JAS 127 mm 32 mm Answers: (a) NB- IN, ca N Pris (b) N

Answer 1

Pmin 9.35 = 4.675 N 2 Equating moment about 4-asis to zero. {My=0 - 127 Pt Fsx 45 - 88 D₂=0 -127 x 4.675 + 26.4 x 45 -88 Dz=0 D₂ = 6.75N Hence the results, Pmin. = 9.35 N. B = 15.85 N C = 13.84 N. For Pmin. = I D₂ = 6.75N