A force of 600 N stretches a certain spring a distance of 0.300 m .
Part A)
What is the potential energy of the spring when it is stretched a distance of 0.300 m ?
Part B)
What is its potential energy when it is compressed a distance of 6.00 cm ?
We know that Magnitude of force F=KX
K=F/X=600/0.3
K=2000N/m
PART A)
We know that potential energy of the spring
U=KX2 /2
here K=2000 N/m , X=0.300 m
U=2000*(0.3)2 /2
U=90 J Answer.
part B)
here X=6.00 cm=0.06 m
U=2000*(0.06)2 /2
U=3.60 J Answer
A force of 600 N stretches a certain spring a distance of 0.300 m . Part...
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