Question

10/28/2019 9. A spring with a spring constant of 25 N/m is stretched 65 cm. What was the force used? 10. A 25 N force stretches a spring 280 cm. What was the spring constant? 11. A 75 N force stretches a spring 175 cm. What was the proportionality constant? 12. An ideal spring has a spring constant of 15 N/m. The spring is stretched 6 cm. What is the potential energy of the spring?

Answer 1

(9)

Given,

x = 65 cm = 0.65 m

We know,

F=kr

F = 25(0.65)

F = 16.25 N

...(Answer)

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(10)

Given,

x = 280 cm = 2.80 m

We know,

F=kr

25=k(2.80)

=k=8.93 N/m

...(Answer)

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(11)

Given,

x = 175 cm = 1.75 m

We know,

F και η

F = c.

c=

> C= 75 1.75

+c= 42.857 N/m

...(Answer)

NOTE: The proportionality constant in a spring is called the spring constant.

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(12)

Given,

x = 6 cm = 0.06 m

We know,

$PE = \frac{1}{2}kx^2$

$\Rightarrow PE = \frac{1}{2}(15)(0.06)^2$

PE=0.027 J

...(Answer)