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Consider the titration of a 15.2 mL sample of 0.106 M HC2H3O2 with 0.694 M NaOH....

Consider the titration of a 15.2 mL sample of 0.106 M HC2H3O2 with 0.694 M NaOH. Ka(HC2H3O2) = 1.8x10-5 Determine the volume of added base required to reach the equivalence point. Answer in units of milliliters to 4 decimal places.

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Answer #1

= At equivalence point number of moles H2 C2H302 number of males of Naot add added. Let u mL of Naot added At equivalence poi

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