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A gymnast with mass 42.0 kg stands on the end of a uniform balance beam as shown in the figure. The beam is 4.50 m long and has a mass of 230 kg excluding the mass of the two supports Each support is 0.590 m from its end of the beam. In unit-vector notation, what are the forces on the beam due to (a) support 1 and (b) support 2

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Answer #1

Sof. let: Fonce on beom oluo to suppert 1 be Force on heam alue to suport abe Givens bea M beam L = 4.50mn Lengtoh Each suppo

Net torue at support 1o 330x 9-8)|4do-0.59( t (4229.2)(4,50-o.54) 4.50 (6.50) 374 1.64十1609 .3 56-F2 (3.32. 5350. 976 (3.32 5

Q665, 6-1611. Fosce on bean olue to support 11053.9 N Foote on, beam duo to Suppor t 2--16 ll.?W 2-1611구 N

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